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1.85x^2-15x-15=0
a = 1.85; b = -15; c = -15;
Δ = b2-4ac
Δ = -152-4·1.85·(-15)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-4\sqrt{21}}{2*1.85}=\frac{15-4\sqrt{21}}{3.7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+4\sqrt{21}}{2*1.85}=\frac{15+4\sqrt{21}}{3.7} $
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